Transcription: In this lesson we will discuss power relationships in a series circuit. In the series circuit shown, each of the three resistors dissipates power in the form of heat. This power must not exceed the resistor's power rating or it will burn out. Resistor R1 dissipates power P1 equal to the current multiplied by the voltage or I times V1. Because V1 equals I times R1, we now get P equal to I times times R1 or I squared R1. By substitution, we also see that P equals V1 squared divided by R1. The power dissipated in P2 and P3 are similarly derived as shown. Thus, for any number of resistors in serie ...
(.mp4)